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13145271454811 is a prime number
BaseRepresentation
bin1011111101001001111100…
…1111000100110001011011
31201112200020120101001120202
42333102133033010301123
53210333003443023221
643542504312012415
72524500036525536
oct277223717046133
951480216331522
1013145271454811
114208973048961
12158378499110b
137447946c1032
1433633d7b7a1d
1517be13080d0b
hexbf49f3c4c5b

13145271454811 has 2 divisors, whose sum is σ = 13145271454812. Its totient is φ = 13145271454810.

The previous prime is 13145271454741. The next prime is 13145271454813. The reversal of 13145271454811 is 11845417254131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13145271454811 - 242 = 8747224943707 is a prime.

Together with 13145271454813, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13145271454813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572635727405 + 6572635727406.

It is an arithmetic number, because the mean of its divisors is an integer number (6572635727406).

Almost surely, 213145271454811 is an apocalyptic number.

13145271454811 is a deficient number, since it is larger than the sum of its proper divisors (1).

13145271454811 is an equidigital number, since it uses as much as digits as its factorization.

13145271454811 is an evil number, because the sum of its binary digits is even.

The product of its digits is 537600, while the sum is 47.

The spelling of 13145271454811 in words is "thirteen trillion, one hundred forty-five billion, two hundred seventy-one million, four hundred fifty-four thousand, eight hundred eleven".