Base | Representation |
---|---|
bin | 1011111101001001111111… |
… | …1001000111010100110101 |
3 | 1201112200021100002221212122 |
4 | 2333102133321013110311 |
5 | 3210333014303202232 |
6 | 43542505344125325 |
7 | 2524500232305356 |
oct | 277223771072465 |
9 | 51480240087778 |
10 | 13145282475317 |
11 | 4208979295813 |
12 | 1583788606845 |
13 | 744796a7c245 |
14 | 336341045d2d |
15 | 17be1400b312 |
hex | bf49fe47535 |
13145282475317 has 2 divisors, whose sum is σ = 13145282475318. Its totient is φ = 13145282475316.
The previous prime is 13145282475271. The next prime is 13145282475373. The reversal of 13145282475317 is 71357428254131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10805624670481 + 2339657804836 = 3287191^2 + 1529594^2 .
It is a cyclic number.
It is not a de Polignac number, because 13145282475317 - 212 = 13145282471221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13145282472317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572641237658 + 6572641237659.
It is an arithmetic number, because the mean of its divisors is an integer number (6572641237659).
Almost surely, 213145282475317 is an apocalyptic number.
It is an amenable number.
13145282475317 is a deficient number, since it is larger than the sum of its proper divisors (1).
13145282475317 is an equidigital number, since it uses as much as digits as its factorization.
13145282475317 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5644800, while the sum is 53.
The spelling of 13145282475317 in words is "thirteen trillion, one hundred forty-five billion, two hundred eighty-two million, four hundred seventy-five thousand, three hundred seventeen".
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