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13145282475317 is a prime number
BaseRepresentation
bin1011111101001001111111…
…1001000111010100110101
31201112200021100002221212122
42333102133321013110311
53210333014303202232
643542505344125325
72524500232305356
oct277223771072465
951480240087778
1013145282475317
114208979295813
121583788606845
13744796a7c245
14336341045d2d
1517be1400b312
hexbf49fe47535

13145282475317 has 2 divisors, whose sum is σ = 13145282475318. Its totient is φ = 13145282475316.

The previous prime is 13145282475271. The next prime is 13145282475373. The reversal of 13145282475317 is 71357428254131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10805624670481 + 2339657804836 = 3287191^2 + 1529594^2 .

It is a cyclic number.

It is not a de Polignac number, because 13145282475317 - 212 = 13145282471221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13145282472317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6572641237658 + 6572641237659.

It is an arithmetic number, because the mean of its divisors is an integer number (6572641237659).

Almost surely, 213145282475317 is an apocalyptic number.

It is an amenable number.

13145282475317 is a deficient number, since it is larger than the sum of its proper divisors (1).

13145282475317 is an equidigital number, since it uses as much as digits as its factorization.

13145282475317 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5644800, while the sum is 53.

The spelling of 13145282475317 in words is "thirteen trillion, one hundred forty-five billion, two hundred eighty-two million, four hundred seventy-five thousand, three hundred seventeen".