Base | Representation |
---|---|
bin | 111101001101101000… |
… | …1011010101101101110 |
3 | 110120022020222210200011 |
4 | 1322123101122231232 |
5 | 4123204214200410 |
6 | 140220020323434 |
7 | 12332361005413 |
oct | 1723321325556 |
9 | 416266883604 |
10 | 131454053230 |
11 | 50827427915 |
12 | 2158784357a |
13 | c51c1ca566 |
14 | 651064c10a |
15 | 364583418a |
hex | 1e9b45ab6e |
131454053230 has 32 divisors (see below), whose sum is σ = 244277607168. Its totient is φ = 50879712000.
The previous prime is 131454053221. The next prime is 131454053267. The reversal of 131454053230 is 32350454131.
It is a super-2 number, since 2×1314540532302 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 131454053192 and 131454053201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3640344 + ... + 3676276.
It is an arithmetic number, because the mean of its divisors is an integer number (7633675224).
Almost surely, 2131454053230 is an apocalyptic number.
131454053230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131454053230 is a deficient number, since it is larger than the sum of its proper divisors (112823553938).
131454053230 is a wasteful number, since it uses less digits than its factorization.
131454053230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47772.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 131454053230 in words is "one hundred thirty-one billion, four hundred fifty-four million, fifty-three thousand, two hundred thirty".
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