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131455022320112 = 248215938895007
BaseRepresentation
bin11101111000111011000001…
…111010001100100111110000
3122020102222101112012112212112
4131320323001322030213300
5114212224341203220422
61143325334211544452
736455211666313121
oct3570730172144760
9566388345175775
10131455022320112
113898184208aa47
12128b0a44bbb128
1358472035a3b0a
14246665812a048
15102e6a7e62ee2
hex778ec1e8c9f0

131455022320112 has 10 divisors (see below), whose sum is σ = 254694105745248. Its totient is φ = 65727511160048.

The previous prime is 131455022320057. The next prime is 131455022320117. The reversal of 131455022320112 is 211023220554131.

It is a super-2 number, since 2×1314550223201122 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131455022320117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4107969447488 + ... + 4107969447519.

Almost surely, 2131455022320112 is an apocalyptic number.

It is an amenable number.

131455022320112 is a deficient number, since it is larger than the sum of its proper divisors (123239083425136).

131455022320112 is an equidigital number, since it uses as much as digits as its factorization.

131455022320112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8215938895015 (or 8215938895009 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 131455022320112 its reverse (211023220554131), we get a palindrome (342478242874243).

The spelling of 131455022320112 in words is "one hundred thirty-one trillion, four hundred fifty-five billion, twenty-two million, three hundred twenty thousand, one hundred twelve".

Divisors: 1 2 4 8 16 8215938895007 16431877790014 32863755580028 65727511160056 131455022320112