Base | Representation |
---|---|
bin | 11101111000111011000001… |
… | …111010001100100111110000 |
3 | 122020102222101112012112212112 |
4 | 131320323001322030213300 |
5 | 114212224341203220422 |
6 | 1143325334211544452 |
7 | 36455211666313121 |
oct | 3570730172144760 |
9 | 566388345175775 |
10 | 131455022320112 |
11 | 3898184208aa47 |
12 | 128b0a44bbb128 |
13 | 58472035a3b0a |
14 | 246665812a048 |
15 | 102e6a7e62ee2 |
hex | 778ec1e8c9f0 |
131455022320112 has 10 divisors (see below), whose sum is σ = 254694105745248. Its totient is φ = 65727511160048.
The previous prime is 131455022320057. The next prime is 131455022320117. The reversal of 131455022320112 is 211023220554131.
It is a super-2 number, since 2×1314550223201122 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131455022320117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4107969447488 + ... + 4107969447519.
Almost surely, 2131455022320112 is an apocalyptic number.
It is an amenable number.
131455022320112 is a deficient number, since it is larger than the sum of its proper divisors (123239083425136).
131455022320112 is an equidigital number, since it uses as much as digits as its factorization.
131455022320112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8215938895015 (or 8215938895009 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 131455022320112 its reverse (211023220554131), we get a palindrome (342478242874243).
The spelling of 131455022320112 in words is "one hundred thirty-one trillion, four hundred fifty-five billion, twenty-two million, three hundred twenty thousand, one hundred twelve".
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