131466020740 has 24 divisors (see below), whose sum is σ = 285598598040. Its totient is φ = 50773083648.

The previous prime is 131466020737. The next prime is 131466020743. The reversal of 131466020740 is 47020664131.

It is an interprime number because it is at equal distance from previous prime (131466020737) and next prime (131466020743).

It can be written as a sum of positive squares in 4 ways, for example, as 2451438144 + 129014582596 = 49512^2 + 359186^2 .

It is a super-2 number, since 2×131466020740² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131466020696 and 131466020705.

It is not an unprimeable number, because it can be changed into a prime (131466020743) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 113332197 + ... + 113333356.

It is an arithmetic number, because the mean of its divisors is an integer number (11899941585).

Almost surely, 2^131466020740 is an apocalyptic number.

131466020740 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131466020740 is an abundant number, since it is smaller than the sum of its proper divisors (154132577300).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131466020740 is a wasteful number, since it uses less digits than its factorization.

131466020740 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 226665591 (or 226665589 counting only the distinct ones).

The product of its (nonzero) digits is 24192, while the sum is 34.

Adding to 131466020740 its reverse (47020664131), we get a palindrome (178486684871).

The spelling of 131466020740 in words is "one hundred thirty-one billion, four hundred sixty-six million, twenty thousand, seven hundred forty".