Base | Representation |
---|---|
bin | 11000011111011010… |
… | …00110101110000010 |
3 | 1020221100000010020000 |
4 | 30033231012232002 |
5 | 203411441243010 |
6 | 10012411300430 |
7 | 643554264300 |
oct | 141755065602 |
9 | 36840003200 |
10 | 13148384130 |
11 | 5637a13672 |
12 | 266b44a716 |
13 | 131705626b |
14 | 8ca353270 |
15 | 51e4b27c0 |
hex | 30fb46b82 |
13148384130 has 120 divisors (see below), whose sum is σ = 41126838588. Its totient is φ = 3005335872.
The previous prime is 13148384129. The next prime is 13148384131. The reversal of 13148384130 is 3148384131.
It is a happy number.
13148384130 is a `hidden beast` number, since 1 + 3 + 148 + 384 + 130 = 666.
13148384130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13148384129) and next prime (13148384131).
It can be written as a sum of positive squares in 2 ways, for example, as 12873852369 + 274531761 = 113463^2 + 16569^2 .
It is not an unprimeable number, because it can be changed into a prime (13148384131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 125949 + ... + 205328.
Almost surely, 213148384130 is an apocalyptic number.
13148384130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13148384130 is an abundant number, since it is smaller than the sum of its proper divisors (27978454458).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13148384130 is a wasteful number, since it uses less digits than its factorization.
13148384130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 331310 (or 331294 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 36.
Subtracting from 13148384130 its reverse (3148384131), we obtain a palindrome (9999999999).
The spelling of 13148384130 in words is "thirteen billion, one hundred forty-eight million, three hundred eighty-four thousand, one hundred thirty".
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