Base | Representation |
---|---|
bin | 11000011111100100… |
… | …01111101011001101 |
3 | 1020221102112120111211 |
4 | 30033302033223031 |
5 | 203412312402113 |
6 | 10012500214421 |
7 | 643601605501 |
oct | 141762175315 |
9 | 36842476454 |
10 | 13149731533 |
11 | 5638753a24 |
12 | 266b99a411 |
13 | 1317408643 |
14 | 8ca5c4301 |
15 | 51e67bb3d |
hex | 30fc8facd |
13149731533 has 2 divisors, whose sum is σ = 13149731534. Its totient is φ = 13149731532.
The previous prime is 13149731531. The next prime is 13149731593. The reversal of 13149731533 is 33513794131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12507514569 + 642216964 = 111837^2 + 25342^2 .
It is a cyclic number.
It is not a de Polignac number, because 13149731533 - 21 = 13149731531 is a prime.
Together with 13149731531, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13149731531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6574865766 + 6574865767.
It is an arithmetic number, because the mean of its divisors is an integer number (6574865767).
Almost surely, 213149731533 is an apocalyptic number.
It is an amenable number.
13149731533 is a deficient number, since it is larger than the sum of its proper divisors (1).
13149731533 is an equidigital number, since it uses as much as digits as its factorization.
13149731533 is an evil number, because the sum of its binary digits is even.
The product of its digits is 102060, while the sum is 40.
The spelling of 13149731533 in words is "thirteen billion, one hundred forty-nine million, seven hundred thirty-one thousand, five hundred thirty-three".
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