Base | Representation |
---|---|
bin | 111101001111001111… |
… | …0000101011100100111 |
3 | 110120102222221121221102 |
4 | 1322132132011130213 |
5 | 4123311433040024 |
6 | 140225214310315 |
7 | 12333612024422 |
oct | 1723636053447 |
9 | 416388847842 |
10 | 131507705639 |
11 | 50854742752 |
12 | 215a17b839b |
13 | c52a36424b |
14 | 65178169b9 |
15 | 364a3d11ae |
hex | 1e9e785727 |
131507705639 has 2 divisors, whose sum is σ = 131507705640. Its totient is φ = 131507705638.
The previous prime is 131507705611. The next prime is 131507705663. The reversal of 131507705639 is 936507705131.
It is a strong prime.
It is an emirp because it is prime and its reverse (936507705131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131507705639 - 212 = 131507701543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131507705593 and 131507705602.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131507705669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65753852819 + 65753852820.
It is an arithmetic number, because the mean of its divisors is an integer number (65753852820).
Almost surely, 2131507705639 is an apocalyptic number.
131507705639 is a deficient number, since it is larger than the sum of its proper divisors (1).
131507705639 is an equidigital number, since it uses as much as digits as its factorization.
131507705639 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 595350, while the sum is 47.
The spelling of 131507705639 in words is "one hundred thirty-one billion, five hundred seven million, seven hundred five thousand, six hundred thirty-nine".
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