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131512513751 is a prime number
BaseRepresentation
bin111101001111011000…
…0011011010011010111
3110120110022222220102122
41322132300123103113
54123314200420001
6140225505330155
712334000631303
oct1723660332327
9416408886378
10131512513751
11508574270a3
12215a333695b
13c52b358898
146518308d03
15364aa30b1b
hex1e9ec1b4d7

131512513751 has 2 divisors, whose sum is σ = 131512513752. Its totient is φ = 131512513750.

The previous prime is 131512513729. The next prime is 131512513753. The reversal of 131512513751 is 157315215131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131512513751 is a prime.

Together with 131512513753, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131512513753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65756256875 + 65756256876.

It is an arithmetic number, because the mean of its divisors is an integer number (65756256876).

Almost surely, 2131512513751 is an apocalyptic number.

131512513751 is a deficient number, since it is larger than the sum of its proper divisors (1).

131512513751 is an equidigital number, since it uses as much as digits as its factorization.

131512513751 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15750, while the sum is 35.

Adding to 131512513751 its reverse (157315215131), we get a palindrome (288827728882).

The spelling of 131512513751 in words is "one hundred thirty-one billion, five hundred twelve million, five hundred thirteen thousand, seven hundred fifty-one".