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1315140050444 = 2211137218171873
BaseRepresentation
bin10011001000110100011…
…101001001111000001100
311122201121101000201000012
4103020310131021320030
5133021401323103234
62444100023252352
7164005252661213
oct23106435117014
94581541021005
101315140050444
11467825300180
12192a718aa0b8
139702b96a77c
144792022807a
15243231a10ce
hex13234749e0c

1315140050444 has 24 divisors (see below), whose sum is σ = 2529048363408. Its totient is φ = 593427491840.

The previous prime is 1315140050431. The next prime is 1315140050489. The reversal of 1315140050444 is 4440500415131.

It is a super-3 number, since 3×13151400504443 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1315140050444.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109079909 + ... + 109091964.

It is an arithmetic number, because the mean of its divisors is an integer number (105377015142).

Almost surely, 21315140050444 is an apocalyptic number.

It is an amenable number.

1315140050444 is a deficient number, since it is larger than the sum of its proper divisors (1213908312964).

1315140050444 is a wasteful number, since it uses less digits than its factorization.

1315140050444 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 218172025 (or 218172023 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1315140050444 its reverse (4440500415131), we get a palindrome (5755640465575).

The spelling of 1315140050444 in words is "one trillion, three hundred fifteen billion, one hundred forty million, fifty thousand, four hundred forty-four".

Divisors: 1 2 4 11 22 44 137 274 548 1507 3014 6028 218171873 436343746 872687492 2399890603 4799781206 9599562412 29889546601 59779093202 119558186404 328785012611 657570025222 1315140050444