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131520711031 is a prime number
BaseRepresentation
bin111101001111100111…
…1101100100101110111
3110120110220102100222121
41322133033230211313
54123323300223111
6140230401140411
712334130412133
oct1723717544567
9416426370877
10131520711031
1150861015906
12215a602a707
13c52cc68a48
1465194403c3
15364b5ee871
hex1e9f3ec977

131520711031 has 2 divisors, whose sum is σ = 131520711032. Its totient is φ = 131520711030.

The previous prime is 131520711019. The next prime is 131520711181. The reversal of 131520711031 is 130117025131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131520711031 - 213 = 131520702839 is a prime.

It is a super-2 number, since 2×1315207110312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131520710987 and 131520711005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131520711001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65760355515 + 65760355516.

It is an arithmetic number, because the mean of its divisors is an integer number (65760355516).

Almost surely, 2131520711031 is an apocalyptic number.

131520711031 is a deficient number, since it is larger than the sum of its proper divisors (1).

131520711031 is an equidigital number, since it uses as much as digits as its factorization.

131520711031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 630, while the sum is 25.

Adding to 131520711031 its reverse (130117025131), we get a palindrome (261637736162).

The spelling of 131520711031 in words is "one hundred thirty-one billion, five hundred twenty million, seven hundred eleven thousand, thirty-one".