Search a number
-
+
1315260849901 is a prime number
BaseRepresentation
bin10011001000111011101…
…001111101111011101101
311122201220210022221201011
4103020323221331323231
5133022123234144101
62444120020345221
7164011250522215
oct23107351757355
94581823287634
101315260849901
11467887508639
12192aa6245211
139704a9b453b
14479322b1245
152432dab3751
hex1323ba7deed

1315260849901 has 2 divisors, whose sum is σ = 1315260849902. Its totient is φ = 1315260849900.

The previous prime is 1315260849893. The next prime is 1315260849907. The reversal of 1315260849901 is 1099480625131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 878908125001 + 436352724900 = 937501^2 + 660570^2 .

It is a cyclic number.

It is not a de Polignac number, because 1315260849901 - 23 = 1315260849893 is a prime.

It is a super-2 number, since 2×13152608499012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1315260849907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657630424950 + 657630424951.

It is an arithmetic number, because the mean of its divisors is an integer number (657630424951).

Almost surely, 21315260849901 is an apocalyptic number.

It is an amenable number.

1315260849901 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315260849901 is an equidigital number, since it uses as much as digits as its factorization.

1315260849901 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 466560, while the sum is 49.

The spelling of 1315260849901 in words is "one trillion, three hundred fifteen billion, two hundred sixty million, eight hundred forty-nine thousand, nine hundred one".