Base | Representation |
---|---|
bin | 111101001111111010… |
… | …1001101010100010111 |
3 | 110120111120220221211201 |
4 | 1322133311031110113 |
5 | 4123333304410112 |
6 | 140231352013331 |
7 | 12334310115643 |
oct | 1723765152427 |
9 | 416446827751 |
10 | 131530544407 |
11 | 50866621869 |
12 | 215a9391247 |
13 | c531ccc802 |
14 | 651a87dc23 |
15 | 364c3e3257 |
hex | 1e9fd4d517 |
131530544407 has 2 divisors, whose sum is σ = 131530544408. Its totient is φ = 131530544406.
The previous prime is 131530544393. The next prime is 131530544437. The reversal of 131530544407 is 704445035131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131530544407 - 223 = 131522155799 is a prime.
It is a super-2 number, since 2×1315305444072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131530544437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65765272203 + 65765272204.
It is an arithmetic number, because the mean of its divisors is an integer number (65765272204).
Almost surely, 2131530544407 is an apocalyptic number.
131530544407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131530544407 is an equidigital number, since it uses as much as digits as its factorization.
131530544407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 37.
Adding to 131530544407 its reverse (704445035131), we get a palindrome (835975579538).
The spelling of 131530544407 in words is "one hundred thirty-one billion, five hundred thirty million, five hundred forty-four thousand, four hundred seven".
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