Base | Representation |
---|---|
bin | 11101111010000011110010… |
… | …001101111000111100101000 |
3 | 122020201110000211112122002010 |
4 | 131322003302031320330220 |
5 | 114220014333400400404 |
6 | 1143425254044035520 |
7 | 36463645611324231 |
oct | 3572036215707450 |
9 | 566643024478063 |
10 | 131533142200104 |
11 | 38a0198a78a037 |
12 | 12904007232ba0 |
13 | 58516a3045988 |
14 | 246a3492d4088 |
15 | 103172b34e189 |
hex | 77a0f2378f28 |
131533142200104 has 32 divisors (see below), whose sum is σ = 337720229975520. Its totient is φ = 42659397470016.
The previous prime is 131533142200091. The next prime is 131533142200111. The reversal of 131533142200104 is 401002241335131.
It is a super-2 number, since 2×1315331422001042 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74061453054 + ... + 74061454829.
It is an arithmetic number, because the mean of its divisors is an integer number (10553757186735).
Almost surely, 2131533142200104 is an apocalyptic number.
It is an amenable number.
131533142200104 is an abundant number, since it is smaller than the sum of its proper divisors (206187087775416).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131533142200104 is a wasteful number, since it uses less digits than its factorization.
131533142200104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 148122907929 (or 148122907925 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 131533142200104 its reverse (401002241335131), we get a palindrome (532535383535235).
The spelling of 131533142200104 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, one hundred forty-two million, two hundred thousand, one hundred four".
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