Base | Representation |
---|---|
bin | 10011001000111111111… |
… | …100001100000010011011 |
3 | 11122202002210121002201002 |
4 | 103020333330030002123 |
5 | 133022300140011011 |
6 | 2444131105215215 |
7 | 164013112530152 |
oct | 23107774140233 |
9 | 4582083532632 |
10 | 1315332735131 |
11 | 467914047018 |
12 | 192b0633150b |
13 | 9705c86318c |
14 | 4793ba64599 |
15 | 24335062c3b |
hex | 1323ff0c09b |
1315332735131 has 2 divisors, whose sum is σ = 1315332735132. Its totient is φ = 1315332735130.
The previous prime is 1315332735113. The next prime is 1315332735149. The reversal of 1315332735131 is 1315372335131.
Together with previous prime (1315332735113) it forms an Ormiston pair, because they use the same digits, order apart.
It is a balanced prime because it is at equal distance from previous prime (1315332735113) and next prime (1315332735149).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1315332735131 is a prime.
It is a super-2 number, since 2×13153327351312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1315334735131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657666367565 + 657666367566.
It is an arithmetic number, because the mean of its divisors is an integer number (657666367566).
Almost surely, 21315332735131 is an apocalyptic number.
1315332735131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315332735131 is an equidigital number, since it uses as much as digits as its factorization.
1315332735131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 85050, while the sum is 38.
The spelling of 1315332735131 in words is "one trillion, three hundred fifteen billion, three hundred thirty-two million, seven hundred thirty-five thousand, one hundred thirty-one".
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