Base | Representation |
---|---|
bin | 1011111101101011101000… |
… | …1110011100111110011111 |
3 | 1201120112120202220200101012 |
4 | 2333122322032130332133 |
5 | 3211010013414224411 |
6 | 43551001501405435 |
7 | 2525240111635064 |
oct | 277327216347637 |
9 | 51515522820335 |
10 | 13154314211231 |
11 | 4211793492676 |
12 | 158548926987b |
13 | 7455a5c9168b |
14 | 33695a75cc6b |
15 | 17c291da618b |
hex | bf6ba39cf9f |
13154314211231 has 2 divisors, whose sum is σ = 13154314211232. Its totient is φ = 13154314211230.
The previous prime is 13154314211219. The next prime is 13154314211239. The reversal of 13154314211231 is 13211241345131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13154314211231 - 26 = 13154314211167 is a prime.
It is a super-2 number, since 2×131543142112312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13154314211239) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577157105615 + 6577157105616.
It is an arithmetic number, because the mean of its divisors is an integer number (6577157105616).
Almost surely, 213154314211231 is an apocalyptic number.
13154314211231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154314211231 is an equidigital number, since it uses as much as digits as its factorization.
13154314211231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8640, while the sum is 32.
Adding to 13154314211231 its reverse (13211241345131), we get a palindrome (26365555556362).
The spelling of 13154314211231 in words is "thirteen trillion, one hundred fifty-four billion, three hundred fourteen million, two hundred eleven thousand, two hundred thirty-one".
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