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131544012501052 = 22157229914694271
BaseRepresentation
bin11101111010001101111010…
…001000110011000000111100
3122020202111002101221010122221
4131322031322020303000330
5114220204114200013202
61143434252440215124
736464512154341564
oct3572157210630074
9566674071833587
10131544012501052
1138a06558791028
121290613b76a4a4
13585271612b808
14246aa9ac81da4
151031b6581e037
hex77a37a23303c

131544012501052 has 24 divisors (see below), whose sum is σ = 232679928911360. Its totient is φ = 65067691590720.

The previous prime is 131544012501043. The next prime is 131544012501067. The reversal of 131544012501052 is 250105210445131.

It is a super-2 number, since 2×1315440125010522 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131544012500999 and 131544012501017.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 457203324 + ... + 457490947.

Almost surely, 2131544012501052 is an apocalyptic number.

It is an amenable number.

131544012501052 is a deficient number, since it is larger than the sum of its proper divisors (101135916410308).

131544012501052 is a wasteful number, since it uses less digits than its factorization.

131544012501052 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 914694661 (or 914694659 counting only the distinct ones).

The product of its (nonzero) digits is 24000, while the sum is 34.

Adding to 131544012501052 its reverse (250105210445131), we get a palindrome (381649222946183).

The spelling of 131544012501052 in words is "one hundred thirty-one trillion, five hundred forty-four billion, twelve million, five hundred one thousand, fifty-two".

Divisors: 1 2 4 157 229 314 458 628 916 35953 71906 143812 914694271 1829388542 3658777084 143607000547 209464988059 287214001094 418929976118 574428002188 837859952236 32886003125263 65772006250526 131544012501052