Base | Representation |
---|---|
bin | 11101111010001101111010… |
… | …001000110011000000111100 |
3 | 122020202111002101221010122221 |
4 | 131322031322020303000330 |
5 | 114220204114200013202 |
6 | 1143434252440215124 |
7 | 36464512154341564 |
oct | 3572157210630074 |
9 | 566674071833587 |
10 | 131544012501052 |
11 | 38a06558791028 |
12 | 1290613b76a4a4 |
13 | 585271612b808 |
14 | 246aa9ac81da4 |
15 | 1031b6581e037 |
hex | 77a37a23303c |
131544012501052 has 24 divisors (see below), whose sum is σ = 232679928911360. Its totient is φ = 65067691590720.
The previous prime is 131544012501043. The next prime is 131544012501067. The reversal of 131544012501052 is 250105210445131.
It is a super-2 number, since 2×1315440125010522 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131544012500999 and 131544012501017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 457203324 + ... + 457490947.
Almost surely, 2131544012501052 is an apocalyptic number.
It is an amenable number.
131544012501052 is a deficient number, since it is larger than the sum of its proper divisors (101135916410308).
131544012501052 is a wasteful number, since it uses less digits than its factorization.
131544012501052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 914694661 (or 914694659 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 34.
Adding to 131544012501052 its reverse (250105210445131), we get a palindrome (381649222946183).
The spelling of 131544012501052 in words is "one hundred thirty-one trillion, five hundred forty-four billion, twelve million, five hundred one thousand, fifty-two".
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