Search a number
-
+
131544392156909 is a prime number
BaseRepresentation
bin11101111010001110010000…
…110001000100011011101101
3122020202112001212022122120222
4131322032100301010123231
5114220210403343010114
61143434354241421125
736464524444352144
oct3572162061043355
9566675055278528
10131544392156909
1138a067330210a6
121290622693a7a5
135852776999154
14246aad546c75b
151031b88d1498e
hex77a390c446ed

131544392156909 has 2 divisors, whose sum is σ = 131544392156910. Its totient is φ = 131544392156908.

The previous prime is 131544392156867. The next prime is 131544392156963. The reversal of 131544392156909 is 909651293445131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113249567366884 + 18294824790025 = 10641878^2 + 4277245^2 .

It is a cyclic number.

It is not a de Polignac number, because 131544392156909 - 212 = 131544392152813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131544392156509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65772196078454 + 65772196078455.

It is an arithmetic number, because the mean of its divisors is an integer number (65772196078455).

Almost surely, 2131544392156909 is an apocalyptic number.

It is an amenable number.

131544392156909 is a deficient number, since it is larger than the sum of its proper divisors (1).

131544392156909 is an equidigital number, since it uses as much as digits as its factorization.

131544392156909 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31492800, while the sum is 62.

The spelling of 131544392156909 in words is "one hundred thirty-one trillion, five hundred forty-four billion, three hundred ninety-two million, one hundred fifty-six thousand, nine hundred nine".