13155323043450 has 48 divisors (see below), whose sum is σ = 37285944171840. Its totient is φ = 3006930981120.

The previous prime is 13155323043433. The next prime is 13155323043493. The reversal of 13155323043450 is 5434032355131.

It is a junction number, because it is equal to n+sod(n) for n = 13155323043399 and 13155323043408.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6264438495 + ... + 6264440594.

It is an arithmetic number, because the mean of its divisors is an integer number (776790503580).

Almost surely, 2^{13155323043450} is an apocalyptic number.

13155323043450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13155323043450 is an abundant number, since it is smaller than the sum of its proper divisors (24130621128390).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13155323043450 is a wasteful number, since it uses less digits than its factorization.

13155323043450 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12528879111 (or 12528879106 counting only the distinct ones).

The product of its (nonzero) digits is 324000, while the sum is 39.

Adding to 13155323043450 its reverse (5434032355131), we get a palindrome (18589355398581).

The spelling of 13155323043450 in words is "thirteen trillion, one hundred fifty-five billion, three hundred twenty-three million, forty-three thousand, four hundred fifty".