Base | Representation |
---|---|
bin | 1011111101101111011011… |
… | …1001000000100100101111 |
3 | 1201120122012201001201011021 |
4 | 2333123312321000210233 |
5 | 3211014104443000142 |
6 | 43551250500235011 |
7 | 2525304250665316 |
oct | 277336671004457 |
9 | 51518181051137 |
10 | 13155332000047 |
11 | 4212165a56456 |
12 | 158571209ba67 |
13 | 745708ab9693 |
14 | 336a159bb27d |
15 | 17c3013ed267 |
hex | bf6f6e4092f |
13155332000047 has 2 divisors, whose sum is σ = 13155332000048. Its totient is φ = 13155332000046.
The previous prime is 13155332000039. The next prime is 13155332000087. The reversal of 13155332000047 is 74000023355131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13155332000047 - 23 = 13155332000039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13155331999976 and 13155332000021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13155332000087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577666000023 + 6577666000024.
It is an arithmetic number, because the mean of its divisors is an integer number (6577666000024).
Almost surely, 213155332000047 is an apocalyptic number.
13155332000047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155332000047 is an equidigital number, since it uses as much as digits as its factorization.
13155332000047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 37800, while the sum is 34.
Adding to 13155332000047 its reverse (74000023355131), we get a palindrome (87155355355178).
The spelling of 13155332000047 in words is "thirteen trillion, one hundred fifty-five billion, three hundred thirty-two million, forty-seven", and thus it is an aban number.
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