Base | Representation |
---|---|
bin | 1011111101101111101100… |
… | …1111100100110000110110 |
3 | 1201120122101210110201121121 |
4 | 2333123323033210300312 |
5 | 3211014232141234220 |
6 | 43551302025334154 |
7 | 2525306125456123 |
oct | 277337317446066 |
9 | 51518353421547 |
10 | 13155405024310 |
11 | 42121a31a268a |
12 | 158573263735a |
13 | 74571ac768c3 |
14 | 336a2158974a |
15 | 17c307a24eaa |
hex | bf6fb3e4c36 |
13155405024310 has 16 divisors (see below), whose sum is σ = 24443591271552. Its totient is φ = 5092414848000.
The previous prime is 13155405024233. The next prime is 13155405024317. The reversal of 13155405024310 is 1342050455131.
It is a super-2 number, since 2×131554050243102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13155405024317) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21218394891 + ... + 21218395510.
It is an arithmetic number, because the mean of its divisors is an integer number (1527724454472).
Almost surely, 213155405024310 is an apocalyptic number.
13155405024310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13155405024310 is a deficient number, since it is larger than the sum of its proper divisors (11288186247242).
13155405024310 is a wasteful number, since it uses less digits than its factorization.
13155405024310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42436790439.
The product of its (nonzero) digits is 36000, while the sum is 34.
Adding to 13155405024310 its reverse (1342050455131), we get a palindrome (14497455479441).
The spelling of 13155405024310 in words is "thirteen trillion, one hundred fifty-five billion, four hundred five million, twenty-four thousand, three hundred ten".
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