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131555123437 is a prime number
BaseRepresentation
bin111101010000101001…
…0111110000011101101
3110120120022011200221011
41322201102332003231
54123411102422222
6140234030505221
712335026045633
oct1724122760355
9416508150834
10131555123437
115087948a411
12215b5665211
13c53712720a
14651dc3b353
15364e64ac77
hex1ea14be0ed

131555123437 has 2 divisors, whose sum is σ = 131555123438. Its totient is φ = 131555123436.

The previous prime is 131555123423. The next prime is 131555123477. The reversal of 131555123437 is 734321555131.

It is an a-pointer prime, because the next prime (131555123477) can be obtained adding 131555123437 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104470521961 + 27084601476 = 323219^2 + 164574^2 .

It is a cyclic number.

It is not a de Polignac number, because 131555123437 - 211 = 131555121389 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131555123437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131555123417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65777561718 + 65777561719.

It is an arithmetic number, because the mean of its divisors is an integer number (65777561719).

Almost surely, 2131555123437 is an apocalyptic number.

It is an amenable number.

131555123437 is a deficient number, since it is larger than the sum of its proper divisors (1).

131555123437 is an equidigital number, since it uses as much as digits as its factorization.

131555123437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 189000, while the sum is 40.

Adding to 131555123437 its reverse (734321555131), we get a palindrome (865876678568).

The spelling of 131555123437 in words is "one hundred thirty-one billion, five hundred fifty-five million, one hundred twenty-three thousand, four hundred thirty-seven".