13160150413231 has 2 divisors, whose sum is σ = 13160150413232. Its totient is φ = 13160150413230.

The previous prime is 13160150413213. The next prime is 13160150413237. The reversal of 13160150413231 is 13231405106131.

Together with previous prime (13160150413213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (13231405106131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13160150413231 - 2¹¹ = 13160150411183 is a prime.

It is a super-2 number, since 2×13160150413231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13160150413193 and 13160150413202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13160150413237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580075206615 + 6580075206616.

It is an arithmetic number, because the mean of its divisors is an integer number (6580075206616).

Almost surely, 2^{13160150413231} is an apocalyptic number.

13160150413231 is a deficient number, since it is larger than the sum of its proper divisors (1).

13160150413231 is an equidigital number, since it uses as much as digits as its factorization.

13160150413231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 13160150413231 its reverse (13231405106131), we get a palindrome (26391555519362).

The spelling of 13160150413231 in words is "thirteen trillion, one hundred sixty billion, one hundred fifty million, four hundred thirteen thousand, two hundred thirty-one".