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13161434783933 is a prime number
BaseRepresentation
bin1011111110000110001010…
…1001010010000010111101
31201121012222000112020211002
42333201202221102002331
53211114104301041213
643554140224140045
72525611423542212
oct277414251220275
951535860466732
1013161434783933
1142148078aa2a7
121586935a67625
1374616c2620c7
14337034303b09
1517c55c08a658
hexbf862a520bd

13161434783933 has 2 divisors, whose sum is σ = 13161434783934. Its totient is φ = 13161434783932.

The previous prime is 13161434783897. The next prime is 13161434783963. The reversal of 13161434783933 is 33938743416131.

It is a happy number.

13161434783933 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9781712870329 + 3379721913604 = 3127573^2 + 1838402^2 .

It is a cyclic number.

It is not a de Polignac number, because 13161434783933 - 232 = 13157139816637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13161434783963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580717391966 + 6580717391967.

It is an arithmetic number, because the mean of its divisors is an integer number (6580717391967).

Almost surely, 213161434783933 is an apocalyptic number.

It is an amenable number.

13161434783933 is a deficient number, since it is larger than the sum of its proper divisors (1).

13161434783933 is an equidigital number, since it uses as much as digits as its factorization.

13161434783933 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11757312, while the sum is 56.

The spelling of 13161434783933 in words is "thirteen trillion, one hundred sixty-one billion, four hundred thirty-four million, seven hundred eighty-three thousand, nine hundred thirty-three".