Base | Representation |
---|---|
bin | 10011001001110101101… |
… | …000010101101100101011 |
3 | 11122211102120112202211211 |
4 | 103021311220111230223 |
5 | 133031121234021413 |
6 | 2444400323533551 |
7 | 164044331110135 |
oct | 23116550255453 |
9 | 4584376482754 |
10 | 1316233501483 |
11 | 46823655211a |
12 | 193117b2a2b7 |
13 | 97174367614 |
14 | 479c5540055 |
15 | 2438919183d |
hex | 13275a15b2b |
1316233501483 has 2 divisors, whose sum is σ = 1316233501484. Its totient is φ = 1316233501482.
The previous prime is 1316233501481. The next prime is 1316233501523. The reversal of 1316233501483 is 3841053326131.
It is an a-pointer prime, because the next prime (1316233501523) can be obtained adding 1316233501483 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1316233501483 - 21 = 1316233501481 is a prime.
Together with 1316233501481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1316233501481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658116750741 + 658116750742.
It is an arithmetic number, because the mean of its divisors is an integer number (658116750742).
Almost surely, 21316233501483 is an apocalyptic number.
1316233501483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316233501483 is an equidigital number, since it uses as much as digits as its factorization.
1316233501483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 1316233501483 in words is "one trillion, three hundred sixteen billion, two hundred thirty-three million, five hundred one thousand, four hundred eighty-three".
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