Base | Representation |
---|---|
bin | 111101010010101111… |
… | …1100111011011101100 |
3 | 110120202012200121120210 |
4 | 1322211133213123230 |
5 | 4124032120010000 |
6 | 140245024142420 |
7 | 12336542456616 |
oct | 1724537473354 |
9 | 416665617523 |
10 | 131625547500 |
11 | 50905210017 |
12 | 21615167a10 |
13 | c5488b3a65 |
14 | 652932ddb6 |
15 | 365590c350 |
hex | 1ea57e76ec |
131625547500 has 120 divisors (see below), whose sum is σ = 383981086720. Its totient is φ = 35082216000.
The previous prime is 131625547499. The next prime is 131625547553. The reversal of 131625547500 is 5745526131.
131625547500 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 21649461 + ... + 21655539.
Almost surely, 2131625547500 is an apocalyptic number.
131625547500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131625547500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191990543360).
131625547500 is an abundant number, since it is smaller than the sum of its proper divisors (252355539220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131625547500 is a wasteful number, since it uses less digits than its factorization.
131625547500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8993 (or 8976 counting only the distinct ones).
The product of its (nonzero) digits is 126000, while the sum is 39.
The spelling of 131625547500 in words is "one hundred thirty-one billion, six hundred twenty-five million, five hundred forty-seven thousand, five hundred".
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