Base | Representation |
---|---|
bin | 11101111011111101010100… |
… | …010001000101100100101101 |
3 | 122021011220212012001220111102 |
4 | 131323331110101011210231 |
5 | 114224134111333134201 |
6 | 1144005234531532445 |
7 | 36506245434246326 |
oct | 3573752421054455 |
9 | 567156765056442 |
10 | 131663636224301 |
11 | 38a52264203925 |
12 | 1292536545a125 |
13 | 5860a9b38c5cc |
14 | 24727a823b44d |
15 | 1034d1774a26b |
hex | 77bf5444592d |
131663636224301 has 2 divisors, whose sum is σ = 131663636224302. Its totient is φ = 131663636224300.
The previous prime is 131663636224217. The next prime is 131663636224319. The reversal of 131663636224301 is 103422636366131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79343021800900 + 52320614423401 = 8907470^2 + 7233299^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131663636224301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131663636224361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65831818112150 + 65831818112151.
It is an arithmetic number, because the mean of its divisors is an integer number (65831818112151).
Almost surely, 2131663636224301 is an apocalyptic number.
It is an amenable number.
131663636224301 is a deficient number, since it is larger than the sum of its proper divisors (1).
131663636224301 is an equidigital number, since it uses as much as digits as its factorization.
131663636224301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1679616, while the sum is 47.
The spelling of 131663636224301 in words is "one hundred thirty-one trillion, six hundred sixty-three billion, six hundred thirty-six million, two hundred twenty-four thousand, three hundred one".
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