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131670421241 is a prime number
BaseRepresentation
bin111101010100000101…
…0110010111011111001
3110120212100010102210012
41322220022302323321
54124130111434431
6140253310031305
712340626054062
oct1725012627371
9416770112705
10131670421241
115092857a357
12216281a8535
13c554c95a78
146531291569
15365982322b
hex1ea82b2ef9

131670421241 has 2 divisors, whose sum is σ = 131670421242. Its totient is φ = 131670421240.

The previous prime is 131670421193. The next prime is 131670421243. The reversal of 131670421241 is 142124076131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104471814841 + 27198606400 = 323221^2 + 164920^2 .

It is a cyclic number.

It is not a de Polignac number, because 131670421241 - 26 = 131670421177 is a prime.

Together with 131670421243, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131670421198 and 131670421207.

It is not a weakly prime, because it can be changed into another prime (131670421243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65835210620 + 65835210621.

It is an arithmetic number, because the mean of its divisors is an integer number (65835210621).

Almost surely, 2131670421241 is an apocalyptic number.

It is an amenable number.

131670421241 is a deficient number, since it is larger than the sum of its proper divisors (1).

131670421241 is an equidigital number, since it uses as much as digits as its factorization.

131670421241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 131670421241 its reverse (142124076131), we get a palindrome (273794497372).

The spelling of 131670421241 in words is "one hundred thirty-one billion, six hundred seventy million, four hundred twenty-one thousand, two hundred forty-one".