Base | Representation |
---|---|
bin | 111101010101011001… |
… | …1001001111001111111 |
3 | 110120222102011200122002 |
4 | 1322222303021321333 |
5 | 4124222411234034 |
6 | 140301524012515 |
7 | 12342003151331 |
oct | 1725263117177 |
9 | 416872150562 |
10 | 131714555519 |
11 | 50950484068 |
12 | 2163ab3113b |
13 | c561179321 |
14 | 653709d451 |
15 | 365d63ee7e |
hex | 1eaacc9e7f |
131714555519 has 2 divisors, whose sum is σ = 131714555520. Its totient is φ = 131714555518.
The previous prime is 131714555477. The next prime is 131714555593. The reversal of 131714555519 is 915555417131.
It is a weak prime.
It is an emirp because it is prime and its reverse (915555417131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131714555519 - 28 = 131714555263 is a prime.
It is a super-2 number, since 2×1317145555192 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131714555719) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65857277759 + 65857277760.
It is an arithmetic number, because the mean of its divisors is an integer number (65857277760).
Almost surely, 2131714555519 is an apocalyptic number.
131714555519 is a deficient number, since it is larger than the sum of its proper divisors (1).
131714555519 is an equidigital number, since it uses as much as digits as its factorization.
131714555519 is an evil number, because the sum of its binary digits is even.
The product of its digits is 472500, while the sum is 47.
The spelling of 131714555519 in words is "one hundred thirty-one billion, seven hundred fourteen million, five hundred fifty-five thousand, five hundred nineteen".
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