131778320699999 has 2 divisors, whose sum is σ = 131778320700000. Its totient is φ = 131778320699998.

The previous prime is 131778320699989. The next prime is 131778320700001. The reversal of 131778320699999 is 999996023877131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131778320699999 - 2⁸ = 131778320699743 is a prime.

It is a super-3 number, since 3×131778320699999³ (a number of 43 digits) contains 333 as substring.

Together with 131778320700001, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131778320699929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65889160349999 + 65889160350000.

It is an arithmetic number, because the mean of its divisors is an integer number (65889160350000).

Almost surely, 2^{131778320699999} is an apocalyptic number.

131778320699999 is a deficient number, since it is larger than the sum of its proper divisors (1).

131778320699999 is an equidigital number, since it uses as much as digits as its factorization.

131778320699999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2499898464, while the sum is 83.

The spelling of 131778320699999 in words is "one hundred thirty-one trillion, seven hundred seventy-eight billion, three hundred twenty million, six hundred ninety-nine thousand, nine hundred ninety-nine".