Base | Representation |
---|---|
bin | 10011001100100101110… |
… | …011110010010111111101 |
3 | 11200010001120101111220201 |
4 | 103030211303302113331 |
5 | 133103144424330131 |
6 | 2450005512443501 |
7 | 164210511654601 |
oct | 23144563622775 |
9 | 4603046344821 |
10 | 1319189292541 |
11 | 469512a6774a |
12 | 1938019a9591 |
13 | 97525840603 |
14 | 47bc5d19501 |
15 | 244ad901761 |
hex | 13325cf25fd |
1319189292541 has 2 divisors, whose sum is σ = 1319189292542. Its totient is φ = 1319189292540.
The previous prime is 1319189292539. The next prime is 1319189292557. The reversal of 1319189292541 is 1452929819131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 831098429316 + 488090863225 = 911646^2 + 698635^2 .
It is a cyclic number.
It is not a de Polignac number, because 1319189292541 - 21 = 1319189292539 is a prime.
Together with 1319189292539, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1319189292571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659594646270 + 659594646271.
It is an arithmetic number, because the mean of its divisors is an integer number (659594646271).
Almost surely, 21319189292541 is an apocalyptic number.
It is an amenable number.
1319189292541 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319189292541 is an equidigital number, since it uses as much as digits as its factorization.
1319189292541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 55.
The spelling of 1319189292541 in words is "one trillion, three hundred nineteen billion, one hundred eighty-nine million, two hundred ninety-two thousand, five hundred forty-one".
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