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1319294305493 is a prime number
BaseRepresentation
bin10011001100101100000…
…100011000010011010101
311200010022212222201121022
4103030230010120103111
5133103403320233433
62450024143330525
7164213225366033
oct23145404302325
94603285881538
101319294305493
1146956727250a
12193830bb0a45
139754151aa58
1447bd5c53553
15244b7c46698
hex1332c1184d5

1319294305493 has 2 divisors, whose sum is σ = 1319294305494. Its totient is φ = 1319294305492.

The previous prime is 1319294305411. The next prime is 1319294305499. The reversal of 1319294305493 is 3945034929131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1198241108164 + 121053197329 = 1094642^2 + 347927^2 .

It is an emirp because it is prime and its reverse (3945034929131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1319294305493 - 222 = 1319290111189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1319294305499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659647152746 + 659647152747.

It is an arithmetic number, because the mean of its divisors is an integer number (659647152747).

Almost surely, 21319294305493 is an apocalyptic number.

It is an amenable number.

1319294305493 is a deficient number, since it is larger than the sum of its proper divisors (1).

1319294305493 is an equidigital number, since it uses as much as digits as its factorization.

1319294305493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3149280, while the sum is 53.

The spelling of 1319294305493 in words is "one trillion, three hundred nineteen billion, two hundred ninety-four million, three hundred five thousand, four hundred ninety-three".