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131941127 is a prime number
BaseRepresentation
bin1111101110101…
…00001100000111
3100012021022012102
413313110030013
5232234104002
621031542315
73161324003
oct767241407
9305238172
10131941127
116852835a
123822a99b
1321448196
1413747703
15b8b3a02
hex7dd4307

131941127 has 2 divisors, whose sum is σ = 131941128. Its totient is φ = 131941126.

The previous prime is 131941099. The next prime is 131941129. The reversal of 131941127 is 721149131.

It is a strong prime.

It is an emirp because it is prime and its reverse (721149131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131941127 - 210 = 131940103 is a prime.

Together with 131941129, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131941127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131941129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65970563 + 65970564.

It is an arithmetic number, because the mean of its divisors is an integer number (65970564).

Almost surely, 2131941127 is an apocalyptic number.

131941127 is a deficient number, since it is larger than the sum of its proper divisors (1).

131941127 is an equidigital number, since it uses as much as digits as its factorization.

131941127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512, while the sum is 29.

The square root of 131941127 is about 11486.5628888715. The cubic root of 131941127 is about 509.0886286588.

The spelling of 131941127 in words is "one hundred thirty-one million, nine hundred forty-one thousand, one hundred twenty-seven".