Base | Representation |
---|---|
bin | 111101011100101110… |
… | …1010111111010011111 |
3 | 110121121112222011110212 |
4 | 1322321131113322133 |
5 | 4130223342111332 |
6 | 140342151323035 |
7 | 12351050530235 |
oct | 1727135277237 |
9 | 417545864425 |
10 | 131960503967 |
11 | 50a6729a846 |
12 | 216a938047b |
13 | c5a0100856 |
14 | 655ba02955 |
15 | 36750238b2 |
hex | 1eb9757e9f |
131960503967 has 2 divisors, whose sum is σ = 131960503968. Its totient is φ = 131960503966.
The previous prime is 131960503907. The next prime is 131960504017. The reversal of 131960503967 is 769305069131.
It is an a-pointer prime, because the next prime (131960504017) can be obtained adding 131960503967 to its sum of digits (50).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131960503967 - 214 = 131960487583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131960503907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65980251983 + 65980251984.
It is an arithmetic number, because the mean of its divisors is an integer number (65980251984).
Almost surely, 2131960503967 is an apocalyptic number.
131960503967 is a deficient number, since it is larger than the sum of its proper divisors (1).
131960503967 is an equidigital number, since it uses as much as digits as its factorization.
131960503967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 918540, while the sum is 50.
The spelling of 131960503967 in words is "one hundred thirty-one billion, nine hundred sixty million, five hundred three thousand, nine hundred sixty-seven".
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