Base | Representation |
---|---|
bin | 10011001101001010110… |
… | …010100100100101010111 |
3 | 11200011122210212001100022 |
4 | 103031022302210211113 |
5 | 133110432242342103 |
6 | 2450151234535355 |
7 | 164232054420026 |
oct | 23151262444527 |
9 | 4604583761308 |
10 | 1319809730903 |
11 | 469801205224 |
12 | 19395573755b |
13 | 975c4243cc1 |
14 | 47c444a28bd |
15 | 244e810a138 |
hex | 1334aca4957 |
1319809730903 has 2 divisors, whose sum is σ = 1319809730904. Its totient is φ = 1319809730902.
The previous prime is 1319809730851. The next prime is 1319809730909. The reversal of 1319809730903 is 3090379089131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1319809730903 - 210 = 1319809729879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1319809730909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659904865451 + 659904865452.
It is an arithmetic number, because the mean of its divisors is an integer number (659904865452).
Almost surely, 21319809730903 is an apocalyptic number.
1319809730903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319809730903 is an equidigital number, since it uses as much as digits as its factorization.
1319809730903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1102248, while the sum is 53.
The spelling of 1319809730903 in words is "one trillion, three hundred nineteen billion, eight hundred nine million, seven hundred thirty thousand, nine hundred three".
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