13199983 has 2 divisors, whose sum is σ = 13199984. Its totient is φ = 13199982.

The previous prime is 13199981. The next prime is 13200001. The reversal of 13199983 is 38999131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13199983 - 2¹ = 13199981 is a prime.

It is a super-3 number, since 3×13199983³ (a number of 22 digits) contains 333 as substring.

Together with 13199981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13199981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6599991 + 6599992.

It is an arithmetic number, because the mean of its divisors is an integer number (6599992).

Almost surely, 2^13199983 is an apocalyptic number.

13199983 is a deficient number, since it is larger than the sum of its proper divisors (1).

13199983 is an equidigital number, since it uses as much as digits as its factorization.

13199983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 52488, while the sum is 43.

The square root of 13199983 is about 3633.1780853682. The cubic root of 13199983 is about 236.3330486373. Note that the first 3 decimals are identical.

The spelling of 13199983 in words is "thirteen million, one hundred ninety-nine thousand, nine hundred eighty-three".