Base | Representation |
---|---|
bin | 10011001101010110001… |
… | …001100111101001000101 |
3 | 11200012011002111002100011 |
4 | 103031112021213221011 |
5 | 133111330040301432 |
6 | 2450222203550221 |
7 | 164236560416401 |
oct | 23152611475105 |
9 | 4605132432304 |
10 | 1320000322117 |
11 | 469899851224 |
12 | 1939a952b371 |
13 | 97624885879 |
14 | 47c61916101 |
15 | 24509c06847 |
hex | 13356267a45 |
1320000322117 has 2 divisors, whose sum is σ = 1320000322118. Its totient is φ = 1320000322116.
The previous prime is 1320000322057. The next prime is 1320000322133. The reversal of 1320000322117 is 7112230000231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1319525474436 + 474847681 = 1148706^2 + 21791^2 .
It is a cyclic number.
It is not a de Polignac number, because 1320000322117 - 27 = 1320000321989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320000332117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660000161058 + 660000161059.
It is an arithmetic number, because the mean of its divisors is an integer number (660000161059).
Almost surely, 21320000322117 is an apocalyptic number.
It is an amenable number.
1320000322117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320000322117 is an equidigital number, since it uses as much as digits as its factorization.
1320000322117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 1320000322117 its reverse (7112230000231), we get a palindrome (8432230322348).
The spelling of 1320000322117 in words is "one trillion, three hundred twenty billion, three hundred twenty-two thousand, one hundred seventeen".
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