13200136406417 has 2 divisors, whose sum is σ = 13200136406418. Its totient is φ = 13200136406416.

The previous prime is 13200136406411. The next prime is 13200136406437. The reversal of 13200136406417 is 71460463100231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7997900739136 + 5202235667281 = 2828056^2 + 2280841^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200136406417 - 2¹⁴ = 13200136390033 is a prime.

It is a super-2 number, since 2×13200136406417² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13200136406411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600068203208 + 6600068203209.

It is an arithmetic number, because the mean of its divisors is an integer number (6600068203209).

Almost surely, 2^{13200136406417} is an apocalyptic number.

It is an amenable number.

13200136406417 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200136406417 is an equidigital number, since it uses as much as digits as its factorization.

13200136406417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 38.

Adding to 13200136406417 its reverse (71460463100231), we get a palindrome (84660599506648).

The spelling of 13200136406417 in words is "thirteen trillion, two hundred billion, one hundred thirty-six million, four hundred six thousand, four hundred seventeen".