13200136406437 has 2 divisors, whose sum is σ = 13200136406438. Its totient is φ = 13200136406436.

The previous prime is 13200136406417. The next prime is 13200136406489. The reversal of 13200136406437 is 73460463100231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10004733476676 + 3195402929761 = 3163026^2 + 1787569^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13200136406437 is a prime.

It is a super-2 number, since 2×13200136406437² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13200136406437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200136406417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600068203218 + 6600068203219.

It is an arithmetic number, because the mean of its divisors is an integer number (6600068203219).

Almost surely, 2^{13200136406437} is an apocalyptic number.

It is an amenable number.

13200136406437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200136406437 is an equidigital number, since it uses as much as digits as its factorization.

13200136406437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 40.

Adding to 13200136406437 its reverse (73460463100231), we get a palindrome (86660599506668).

The spelling of 13200136406437 in words is "thirteen trillion, two hundred billion, one hundred thirty-six million, four hundred six thousand, four hundred thirty-seven".