Base | Representation |
---|---|
bin | 11110000000111000100010… |
… | …011010011011110001011111 |
3 | 122022101021111110120111022101 |
4 | 132000320202122123301133 |
5 | 114300210301132330421 |
6 | 1144424532325025531 |
7 | 36542560101652351 |
oct | 3600704232336137 |
9 | 568337443514271 |
10 | 132002102230111 |
11 | 3907286046a673 |
12 | 1297aa84b552a7 |
13 | 588698b5084a9 |
14 | 2484d15d190d1 |
15 | 103da26dce191 |
hex | 780e2269bc5f |
132002102230111 has 2 divisors, whose sum is σ = 132002102230112. Its totient is φ = 132002102230110.
The previous prime is 132002102230109. The next prime is 132002102230121. The reversal of 132002102230111 is 111032201200231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132002102230111 - 21 = 132002102230109 is a prime.
Together with 132002102230109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132002102230121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66001051115055 + 66001051115056.
It is an arithmetic number, because the mean of its divisors is an integer number (66001051115056).
Almost surely, 2132002102230111 is an apocalyptic number.
132002102230111 is a deficient number, since it is larger than the sum of its proper divisors (1).
132002102230111 is an equidigital number, since it uses as much as digits as its factorization.
132002102230111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 132002102230111 its reverse (111032201200231), we get a palindrome (243034303430342).
The spelling of 132002102230111 in words is "one hundred thirty-two trillion, two billion, one hundred two million, two hundred thirty thousand, one hundred eleven".
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