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1320021434140 = 22566001071707
BaseRepresentation
bin10011001101010111011…
…010001001111100011100
311200012012120012200120221
4103031113122021330130
5133111400441343030
62450224240251124
7164240235026443
oct23152732117434
94605176180527
101320021434140
114698aa760a82
121939b4610aa4
13976290681a6
1447c6464dd5a
152450b9c6e7a
hex13357689f1c

1320021434140 has 12 divisors (see below), whose sum is σ = 2772045011736. Its totient is φ = 528008573648.

The previous prime is 1320021434117. The next prime is 1320021434159. The reversal of 1320021434140 is 414341200231.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33000535834 + ... + 33000535873.

It is an arithmetic number, because the mean of its divisors is an integer number (231003750978).

Almost surely, 21320021434140 is an apocalyptic number.

1320021434140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1320021434140 is an abundant number, since it is smaller than the sum of its proper divisors (1452023577596).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320021434140 is a wasteful number, since it uses less digits than its factorization.

1320021434140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66001071716 (or 66001071714 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1320021434140 its reverse (414341200231), we get a palindrome (1734362634371).

The spelling of 1320021434140 in words is "one trillion, three hundred twenty billion, twenty-one million, four hundred thirty-four thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 66001071707 132002143414 264004286828 330005358535 660010717070 1320021434140