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13200231311023 is a prime number
BaseRepresentation
bin1100000000010110101100…
…0110010010011010101111
31201201221002211001000211211
43000011223012102122233
53212233033203423043
644024034052255251
72531454015561511
oct300055306223257
951657084030754
1013200231311023
11422a20649a329
121592362911527
13749a12ba5503
14338c74b19bb1
1517d57d09ca9d
hexc016b1926af

13200231311023 has 2 divisors, whose sum is σ = 13200231311024. Its totient is φ = 13200231311022.

The previous prime is 13200231311021. The next prime is 13200231311101. The reversal of 13200231311023 is 32011313200231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13200231311023 - 21 = 13200231311021 is a prime.

It is a super-3 number, since 3×132002313110233 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13200231311021, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13200231310985 and 13200231311003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13200231311021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600115655511 + 6600115655512.

It is an arithmetic number, because the mean of its divisors is an integer number (6600115655512).

Almost surely, 213200231311023 is an apocalyptic number.

13200231311023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200231311023 is an equidigital number, since it uses as much as digits as its factorization.

13200231311023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13200231311023 its reverse (32011313200231), we get a palindrome (45211544511254).

The spelling of 13200231311023 in words is "thirteen trillion, two hundred billion, two hundred thirty-one million, three hundred eleven thousand, twenty-three".