Base | Representation |
---|---|
bin | 1100000000010110111101… |
… | …0000001101001111101011 |
3 | 1201201221021200012121202221 |
4 | 3000011233100031033223 |
5 | 3212233204030121024 |
6 | 44024045022334511 |
7 | 2531455523234212 |
oct | 300055720151753 |
9 | 51657250177687 |
10 | 13200301020139 |
11 | 422a241881872 |
12 | 159238212a437 |
13 | 749a244717cc |
14 | 338c800a4079 |
15 | 17d58426c3e4 |
hex | c016f40d3eb |
13200301020139 has 2 divisors, whose sum is σ = 13200301020140. Its totient is φ = 13200301020138.
The previous prime is 13200301020037. The next prime is 13200301020143. The reversal of 13200301020139 is 93102010300231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13200301020139 - 29 = 13200301019627 is a prime.
It is not a weakly prime, because it can be changed into another prime (13200301030139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600150510069 + 6600150510070.
It is an arithmetic number, because the mean of its divisors is an integer number (6600150510070).
Almost surely, 213200301020139 is an apocalyptic number.
13200301020139 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200301020139 is an equidigital number, since it uses as much as digits as its factorization.
13200301020139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 13200301020139 in words is "thirteen trillion, two hundred billion, three hundred one million, twenty thousand, one hundred thirty-nine".
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