Base | Representation |
---|---|
bin | 1100000000010110111111… |
… | …1110010101001000111100 |
3 | 1201201221022111221220110022 |
4 | 3000011233332111020330 |
5 | 3212233220124023400 |
6 | 44024050133431312 |
7 | 2531456031062633 |
oct | 300055776251074 |
9 | 51657274856408 |
10 | 13200313111100 |
11 | 422a24868a9a5 |
12 | 159238619b538 |
13 | 749a26b1601b |
14 | 338c8193051a |
15 | 17d585359b85 |
hex | c016ff9523c |
13200313111100 has 18 divisors (see below), whose sum is σ = 28644679451304. Its totient is φ = 5280125244400.
The previous prime is 13200313111043. The next prime is 13200313111189. The reversal of 13200313111100 is 111131300231.
13200313111100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 66001565456 + ... + 66001565655.
It is an arithmetic number, because the mean of its divisors is an integer number (1591371080628).
Almost surely, 213200313111100 is an apocalyptic number.
13200313111100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13200313111100 is an abundant number, since it is smaller than the sum of its proper divisors (15444366340204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13200313111100 is a wasteful number, since it uses less digits than its factorization.
13200313111100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132003131125 (or 132003131118 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13200313111100 its reverse (111131300231), we get a palindrome (13311444411331).
The spelling of 13200313111100 in words is "thirteen trillion, two hundred billion, three hundred thirteen million, one hundred eleven thousand, one hundred".
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