Base | Representation |
---|---|
bin | 1100000000010110111111… |
… | …1111100100001111110101 |
3 | 1201201221022112120100221020 |
4 | 3000011233333210033311 |
5 | 3212233220214411000 |
6 | 44024050144411353 |
7 | 2531456033612415 |
oct | 300055777441765 |
9 | 51657275510836 |
10 | 13200313435125 |
11 | 422a248891393 |
12 | 1592386316b59 |
13 | 749a26bca65b |
14 | 338c819b6645 |
15 | 17d5853c0ba0 |
hex | c016ffe43f5 |
13200313435125 has 64 divisors (see below), whose sum is σ = 22698681857280. Its totient is φ = 6808357920000.
The previous prime is 13200313435123. The next prime is 13200313435151. The reversal of 13200313435125 is 52153431300231.
It is not a de Polignac number, because 13200313435125 - 21 = 13200313435123 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13200313435123) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2423970 + ... + 5681219.
It is an arithmetic number, because the mean of its divisors is an integer number (354666904020).
Almost surely, 213200313435125 is an apocalyptic number.
13200313435125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13200313435125 is a deficient number, since it is larger than the sum of its proper divisors (9498368422155).
13200313435125 is a wasteful number, since it uses less digits than its factorization.
13200313435125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8105351 (or 8105341 counting only the distinct ones).
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 13200313435125 its reverse (52153431300231), we get a palindrome (65353744735356).
The spelling of 13200313435125 in words is "thirteen trillion, two hundred billion, three hundred thirteen million, four hundred thirty-five thousand, one hundred twenty-five".
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