Base | Representation |
---|---|
bin | 1100000000010111010111… |
… | …1011111010100001000111 |
3 | 1201201221120111011221202202 |
4 | 3000011311323322201013 |
5 | 3212233421231003223 |
6 | 44024104105425115 |
7 | 2531461354241321 |
oct | 300056573724107 |
9 | 51657514157682 |
10 | 13200413141063 |
11 | 422a29a0a1995 |
12 | 15923b379b19b |
13 | 749a4176a355 |
14 | 338c90d2c611 |
15 | 17d58e018428 |
hex | c0175efa847 |
13200413141063 has 2 divisors, whose sum is σ = 13200413141064. Its totient is φ = 13200413141062.
The previous prime is 13200413141039. The next prime is 13200413141147. The reversal of 13200413141063 is 36014131400231.
It is a happy number.
13200413141063 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13200413141063 - 228 = 13200144705607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200413101063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600206570531 + 6600206570532.
It is an arithmetic number, because the mean of its divisors is an integer number (6600206570532).
Almost surely, 213200413141063 is an apocalyptic number.
13200413141063 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200413141063 is an equidigital number, since it uses as much as digits as its factorization.
13200413141063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13200413141063 its reverse (36014131400231), we get a palindrome (49214544541294).
The spelling of 13200413141063 in words is "thirteen trillion, two hundred billion, four hundred thirteen million, one hundred forty-one thousand, sixty-three".
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