Base | Representation |
---|---|
bin | 10011001101011100000… |
… | …110010010101101011111 |
3 | 11200012102001021000000221 |
4 | 103031130012102231133 |
5 | 133112031112110442 |
6 | 2450240130502211 |
7 | 164242211551546 |
oct | 23153406225537 |
9 | 4605361230027 |
10 | 1320100113247 |
11 | 46994010a833 |
12 | 193a16a34967 |
13 | 9763c455286 |
14 | 47c70c9115d |
15 | 24513869467 |
hex | 1335c192b5f |
1320100113247 has 2 divisors, whose sum is σ = 1320100113248. Its totient is φ = 1320100113246.
The previous prime is 1320100113209. The next prime is 1320100113253. The reversal of 1320100113247 is 7423110010231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320100113247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320100113257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660050056623 + 660050056624.
It is an arithmetic number, because the mean of its divisors is an integer number (660050056624).
Almost surely, 21320100113247 is an apocalyptic number.
1320100113247 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320100113247 is an equidigital number, since it uses as much as digits as its factorization.
1320100113247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1320100113247 its reverse (7423110010231), we get a palindrome (8743210123478).
The spelling of 1320100113247 in words is "one trillion, three hundred twenty billion, one hundred million, one hundred thirteen thousand, two hundred forty-seven".
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