Base | Representation |
---|---|
bin | 10011001101011100000… |
… | …110101000011000110111 |
3 | 11200012102001102111211112 |
4 | 103031130012220120313 |
5 | 133112031122431124 |
6 | 2450240132425235 |
7 | 164242212401453 |
oct | 23153406503067 |
9 | 4605361374745 |
10 | 1320100202039 |
11 | 469940170513 |
12 | 193a16a7821b |
13 | 9763c486808 |
14 | 47c70cb5663 |
15 | 2451388590e |
hex | 1335c1a8637 |
1320100202039 has 2 divisors, whose sum is σ = 1320100202040. Its totient is φ = 1320100202038.
The previous prime is 1320100201991. The next prime is 1320100202041. The reversal of 1320100202039 is 9302020010231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320100202039 is a prime.
Together with 1320100202041, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1320100202089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660050101019 + 660050101020.
It is an arithmetic number, because the mean of its divisors is an integer number (660050101020).
Almost surely, 21320100202039 is an apocalyptic number.
1320100202039 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320100202039 is an equidigital number, since it uses as much as digits as its factorization.
1320100202039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
The spelling of 1320100202039 in words is "one trillion, three hundred twenty billion, one hundred million, two hundred two thousand, thirty-nine".
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