13201140031 has 2 divisors, whose sum is σ = 13201140032. Its totient is φ = 13201140030.

The previous prime is 13201139983. The next prime is 13201140041. The reversal of 13201140031 is 13004110231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13201140031 - 2¹⁵ = 13201107263 is a prime.

It is a super-2 number, since 2×13201140031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13201139987 and 13201140014.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13201140041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600570015 + 6600570016.

It is an arithmetic number, because the mean of its divisors is an integer number (6600570016).

Almost surely, 2^13201140031 is an apocalyptic number.

13201140031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13201140031 is an equidigital number, since it uses as much as digits as its factorization.

13201140031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13201140031 its reverse (13004110231), we get a palindrome (26205250262).

The spelling of 13201140031 in words is "thirteen billion, two hundred one million, one hundred forty thousand, thirty-one".