Base | Representation |
---|---|
bin | 11000100101101100… |
… | …10110100101001001 |
3 | 1021002000021101201122 |
4 | 30102312112211021 |
5 | 204013442440131 |
6 | 10021534125025 |
7 | 645064560515 |
oct | 142266264511 |
9 | 37060241648 |
10 | 13201140041 |
11 | 56647769a1 |
12 | 2685050775 |
13 | 1324c67b8b |
14 | 8d3367145 |
15 | 523e33d7b |
hex | 312d96949 |
13201140041 has 2 divisors, whose sum is σ = 13201140042. Its totient is φ = 13201140040.
The previous prime is 13201140031. The next prime is 13201140049. The reversal of 13201140041 is 14004110231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10599732025 + 2601408016 = 102955^2 + 51004^2 .
It is an emirp because it is prime and its reverse (14004110231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13201140041 - 214 = 13201123657 is a prime.
It is not a weakly prime, because it can be changed into another prime (13201140049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600570020 + 6600570021.
It is an arithmetic number, because the mean of its divisors is an integer number (6600570021).
Almost surely, 213201140041 is an apocalyptic number.
It is an amenable number.
13201140041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13201140041 is an equidigital number, since it uses as much as digits as its factorization.
13201140041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 13201140041 its reverse (14004110231), we get a palindrome (27205250272).
The spelling of 13201140041 in words is "thirteen billion, two hundred one million, one hundred forty thousand, forty-one".
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